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For this exercise, you need INTERNET EXPLORER 6.0 and above, with MathPlayer installed.

SOLVING ABSOLUTE VALUE EQUATIONS

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The concepts for this exercise are summarized below. For a complete discussion, read the text.
MathPlayer is only required for the concept discussion; it is not required for the web exercise.

THEOREM: solving absolute value equations

Let  x , and let  k0 . Then,

|x|=k          x=± k  .

Translating the theorem:
Recall first that normal mathematical conventions dictate
that " |x|=k  " represents an entire class of sentences,
including  |x|=2  ,  |x|=5.7 , and  |x|= 13 .
The variable  k  changes from sentence to sentence,
but is constant within a given sentence.

Also, " x=±k  " is a shorthand for " x=k  or  x=-k ".

When you see a sentence of the form " |x|=k  ", here's what you should do:

However, the power of the tool    " |x|=k          x=± k  "  
goes way beyond solving simple sentences like    " |x|=5 " !

Since  x  can be any real number, you should think of  x 
as merely representing the stuff inside the absolute value symbols.
Thus, you could think of rewriting the tool as:    " |stuff|=k          stuff=± k  " .
See how this idea is used in the following examples:

EXAMPLES:
Solve:   |2-3x |=7
Solution: Write a nice, clean list of equivalent sentences:
|2-3x |=7 (original equation)
2-3x= ±7 (use the theorem)
2-3x= 7    or    2-3x=- 7 (expand the plus/minus)
-3x=5    or    -3x=-9 (subtract  2  from both sides of both equations)
x=-5 3    or    x=3 (divide both sides of both equations by  -3 )


Solve:   5-2|3 -4x|=- 7
Solution: Write a nice, clean list of equivalent sentences:
5-2|3 -4x|=- 7 (original equation)
-2|3- 4x|=-12 (subtract  5  from both sides)
|3-4x |=6 (divide both sides by  -2 )
3-4x= ±6 (use the theorem)
3-4x= 6    or    3-4x= -6 (expand the plus/minus)
-4x=3    or    -4x=-9 (subtract  3  from both sides of both equations)
x=-3 4    or    x=9 4 (divide both sides of both equations by  -3 )

Solve:   |3x+1 |=-5
Solution:   always false

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However, you can check to see if your answer is correct.  
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Solve: