MORE PRACTICE WITH FUNCTION NOTATION

LESSON READ-THROUGH
by Dr. Carol JVF Burns (website creator)
Follow along with the highlighted text while you listen!
 

Recall from Introduction to Function Notation that a function is a rule that takes an input, does something to it,
and gives a unique corresponding output.

There is a special notation (called ‘function notation’) that is used to represent this situation:
if the function name is $\,f\,$, and the input name is $\,x\,$, then the unique corresponding output is called $\,f(x)\,$.
The notation ‘ $f(x)\,$’ is read aloud as:   ‘ $\,f\,$   of   $\,x\,$ ’.

So, what exactly is $\,f(x)\,$?
Answer: It is the output from the function $\,f\,$ when the input is $\,x\,\,$.

This exercise gives more advanced practice with function notation.

EXAMPLES:
Question:
Let $\,f(x) = x^2 + 2x\,$.
Find and simplify:   $f(-3)$
Solution:
$\cssId{s20}{f(-3)} \cssId{s21}{= (-3)^2 + 2(-3)} \cssId{s22}{= 9 - 6} \cssId{s23}{= 3}$
Question:
Let $\,f(x) = x^2 + 2x\,$.
Find and simplify:   $f(x+1)$
Solution:
$\cssId{s28}{f(x+1)} \cssId{s29}{= (x+1)^2 + 2(x+1)} \cssId{s30}{= x^2 + 2x + 1 + 2x + 2} \cssId{s31}{= x^2 + 4x + 3}$

the ‘Empty Parentheses Method’

Some people find it helpful to use the so-called ‘empty parentheses method’ to help with function evaluation.
For example, take the function rule $\,f(x) = x^2 + 2x\,$ and rewrite it as $$\cssId{s35}{f(\text{blah})} \cssId{s36}{= (\text{blah})^2 + 2(\text{blah})}$$ or, even more simply, just leave a blank space for the input—a pair of empty parentheses where the input should be: $$\cssId{s39}{f(\ \ \ \ )} \cssId{s40}{= (\ \ \ \ )^2 + 2(\ \ \ \ )}$$ Then, when you want to find (say) $\,f(x+1)\,$, just put the input, $\,x+1\,$, inside every set of empty parentheses: $$\cssId{s43}{f(x+1)} \cssId{s44}{= (x+1)^2 + 2(x+1)}$$ Voila!
Question:
Let $\,f(x) = 5\,$.
Find and simplify:   $f(x+1)$
Solution:
The function $\,f\,$ is a constant function:
no matter what the input is, the output is $\,5\,$.
That is, $\,f(\text{anything}) = 5\,$.
So, $\,f(x+1) = 5\,$.
Question:
Let $\,f(x) = x^2 - 2x\,$.
Find and simplify:   $f(1) + f(3)$
Solution:
$\cssId{s58}{f(1) + f(3)}$
$\ \ \cssId{s59}{= \overset{f(1)}{\overbrace{(1^2 - 2\cdot 1)}}} \cssId{s60}{+ \overset{f(3)}{\overbrace{(3^2 - 2\cdot 3)}}}$
$\ \ \cssId{s61}{= (1 - 2) + (9- 6)}$
$\ \ \cssId{s62}{= 2}$
Master the ideas from this section
by practicing the exercise at the bottom of this page.


When you're done practicing, move on to:
Domain and Range of a Function

 
 
CONCEPT QUESTIONS EXERCISE:
On this exercise, you will not key in your answer.
However, you can check to see if your answer is correct.
PROBLEM TYPES:
1 2 3 4 5 6 7 8 9 10 11
AVAILABLE MASTERED IN PROGRESS

(MAX is 11; there are 11 different problem types.)