EXAMPLES:
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$9^{1/2} = \sqrt{9} = 3$
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$(-9)^{1/2} = \sqrt{-9} = \text{nd}$ Input “nd” if an expression is not defined.
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$-9^{1/2} = -\sqrt{9} = -3$
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$\displaystyle 9^{-1/2} = \frac{1}{9^{1/2}} = \frac{1}{\sqrt{9}} = \frac{1}{3}$ Use fraction names, not decimal names.
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$(-8)^{1/3} = \root 3\of{-8} = -2$
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$\displaystyle(-8)^{-1/3} = \frac{1}{(-8)^{1/3}} = \frac{1}{\root 3\of{-8}} = \frac{1}{-2} = -\frac{1}{2}$
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$16^{3/4} = (16^{1/4})^3 = (\root 4\of{16})^3 = 2^3 = 8$
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$\displaystyle 16^{-3/4} = \frac{1}{16^{3/4}} = \frac{1}{(16^{1/4})^3} = \frac{1}{(\root 4\of{16})^3} = \frac{1}{2^3} = \frac{1}{8}$
Master the ideas from this section
by practicing the exercise at the bottom of this page.
When you're done practicing, move on to:
Practice with $\,x\,$ and $\,-x\,$
Feel free to use scrap paper and pencil to compute your answers.
Do not use a calculator for these problems.