EXAMPLES:
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$9^{1/2} = \sqrt{9} = 3$
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$(-9)^{1/2} = \sqrt{-9} = \text{nd}$ Input “nd” if an expression is not defined.
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$-9^{1/2} = -\sqrt{9} = -3$
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$\displaystyle 9^{-1/2} = \frac{1}{9^{1/2}} = \frac{1}{\sqrt{9}} = \frac{1}{3}$ Use fraction names, not decimal names.
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$(-8)^{1/3} = \root 3\of{-8} = -2$
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$\displaystyle(-8)^{-1/3} = \frac{1}{(-8)^{1/3}} = \frac{1}{\root 3\of{-8}} = \frac{1}{-2} = -\frac{1}{2}$
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$16^{3/4} = (16^{1/4})^3 = (\root 4\of{16})^3 = 2^3 = 8$
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$\displaystyle 16^{-3/4} = \frac{1}{16^{3/4}} = \frac{1}{(16^{1/4})^3} = \frac{1}{(\root 4\of{16})^3} = \frac{1}{2^3} = \frac{1}{8}$
On this exercise, you will not key in your answer.
However, you can check to see if your answer is correct.
Feel free to use scrap paper and pencil to compute your answers.
Do not use a calculator for these problems.