THE MIDPOINT FORMULA
The midpoint of the line segment between points
$\,(x_1,y_1)\,$
and
$\,(x_2,y_2)\,$
is given by the Midpoint Formula:
$$
\left(
\frac{x_1+x_2}2,\frac{y_1+y_2}2
\right)
$$
Here,
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$\,x_1\,$ (read as ‘$\,x\,$ sub $\,1\,$’) denotes the $\,x$-value of the first point,
and
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$\,y_1\,$ (read as ‘$\,y\,$ sub $\,1\,$’) denotes the $\,y$-value of the first point.
Similarly,
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$\,x_2\,$ and $\,y_2\,$ denote the $\,x$-value and $\,y$-value of the second point.
Thus, to find the location that is exactly halfway between two points,
you average the x-values, and average the y-values.
The Midpoint Formula follows easily from the following observations:
- The average of two numbers always lies exactly halfway between the two numbers.
- Referring to the sketch below,
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$\Delta ABD\,$
is similar to
$\,\Delta AMC$.
That is, these two triangles have the same angles.
Why? They both share angle $\,A\,$, and they both have a right angle.
Since all the angles in a triangle sum to $\,180^\circ\,$, the third angles must also be the same.
-
Similarity gives us what we need!
It tells us that $\Delta ABD\,$ and $\Delta AMC\,$ have exactly the same shapesthey're just different sizes.
Since
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$\,\overline{AM}\,$ is exactly half of
$\,\overline{AB}\,$,
$\,\overline{AC}\,$ must be exactly half of
$\,\overline{AD}\,$.
Thus, $\,C\,$ is the midpoint between $\,A\,$ and $\,D\,$ (which can be found by averaging $\,x_1\,$ and $\,x_2\,$).
-
Use a similar argument to show that
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$\,\overline{DE}\,$ (which has the same length as $\,\overline{CM}\,$) is exactly half of $\,\overline{DB}\,$.
EXAMPLE:
Question:
Find the midpoint of the line segment between
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$\,(1,-3)\,$ and $\,(-2,5)\,$.
Solution:
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$\displaystyle
\left(
\frac{1+(-2)}2,
\frac{-3 + 5}2
\right)
=
\left(-\frac12,1\right)
$
Question:
Suppose that
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$\,(2,3)\,$ is exactly halfway between $\,(-1,5)\,$ and $\,(x,y)\,$.
Find $\,x\,$ and $\,y\,$.
Solution:
Rephrasing, $\,(2,3)\,$ is the midpoint of the segment with endpoints $\,(-1,5)\,$ and $\,(x,y)\,$.
Thus:
|
$\displaystyle
(2,3) = \left(\frac{-1+x}2,\frac{5+y}2\right)
$
|
use the Midpoint Formula |
| $\displaystyle
2 = \frac{-1+x}2\ $ and $\ \displaystyle 3 = \frac{5+y}2$ |
for ordered pairs to be equal, the first coordinates must be equal and the second coordinates must be equal |
| $4 = -1 + x\ $ and $\ 6 = 5 + y$ |
clear fractions (multiply both sides of both equations by $\,2$) |
$5 = x\ $ and $\ 1 = y$ | finish solving each equation |
$x = 5\ $ and $\ y = 1$ | write your solutions in the conventional way |
On this exercise, you will not key in your answer.
However, you can check to see if your answer is correct.