Here, you will practice factoring trinomials of the form
$\,x^2 + bx + c\,$,
where $\,b\,$ and $\,c\,$ are integers,
and $\,c\lt 0\,$.
That is, the constant term is negative.
Recall that the integers are: $\,\ldots,3,2,1,0,1,2,3,\ldots$
As discussed in Basic Concepts Involved in Factoring Trinomials,
you must first find two numbers that add to $\,b\,$ and that multiply to $\,c\,$, since then:
$$
\,\cssId{s11}{x^2 + bx + c} \ \
\cssId{s12}{=\ \ x^2 + (\overset{=\ b}{\overbrace{f+g}})x + \overset{=\ c}{\overbrace{\ fg\ }}} \ \
\cssId{s13}{=\ \ (x + f)(x + g)}
$$
Since $\,c\,$ is negative in this exercise,
one number will be positive, and the other will be negative.
(How can two numbers multiply to give a negative result?
One must be positive, and the other negative.)
That is, the numbers will have different signs.
When you add numbers that have different signs,
then in your head you actually do a subtraction problem.
For example, to mentally add $\,(5) + 3\,$,
in your head you would compute $\,5  3\,$,
and then assign a negative sign to your answer.
Think of it this way:
Start at zero on a number line.
Walk $\,5\,$ units to the left, and $\,3\,$ units to the right.
You end up at $\,2\,$.
You walked farther to the left than you did to the right,
so your final answer is negative.
The sign of $\,b\,$ (the coefficient of the $\,x\,$ term)
determines which number will be positive, and which will be negative:
If $\,b\gt 0\,$, then the bigger number (the one farthest from zero) will be positive.
If $\,b\lt 0\,$, then the bigger number (the one farthest from zero) will be negative.
In other words, the biggest number takes the sign (plus or minus) of $\,b\,$.
These results are summarized below:
CONCEPT QUESTIONS EXERCISE:
On this exercise, you will not key in your answer.However, you can check to see if your answer is correct. 
PROBLEM TYPES:
