Need some simpler practice with absolute value and related concepts first?

Now, let's talk about the concepts involved in solving absolute value equations:

THEOREM solving absolute value equations
Let $\,x\in\mathbb{R}\,,$ and let $\,k\ge 0\,.$   Then: $$ \cssId{s14}{|x| = k\ \ \text{ is equivalent to }\ \ x = \pm k} $$

Translating the Theorem

Recall first that normal mathematical conventions dictate that   ‘$\,|x| = k\ $’  represents an entire class of sentences, including the members

$|x| = 2$

$|x| = 5.7$

$|x| = \frac{1}{3}$

The variable $\,k\ $ changes from sentence to sentence, but is constant within a given sentence.

Also recall that  ‘$\,x=\pm k\ $’  is a shorthand for  ‘$\,x = k\,$ or $\,x = -k\,$’.

When you see a sentence of the form $\,|x| = k\ $, here’s what you should do:

solving the absolute value sentence |x| = k

Recall that   ‘$\iff$’   is a symbol for ‘is equivalent to’.

The power of the sentence-transforming tool

$$\cssId{s48}{|x| = k \iff x = \pm k}$$

goes far beyond solving simple sentences like $\,|x| = 5\,$!

Since $\,x\,$ can be any real number, you should think of $\,x\,$ as merely representing the stuff inside the absolute value symbols. Thus, you could think of rewriting the tool as:

$$ \cssId{s53}{|\text{stuff}| = k \iff \text{stuff} = \pm k} $$

See how this idea is used in the following examples:

Example

Solve: $|2 - 3x| = 7$
Solution: Write a nice, clean list of equivalent sentences:
$|2 - 3x| = 7$ original equation
$2-3x = \pm 7$ check that $\,k\ge 0\,$; use the theorem
$2-3x = 7\ \text{ or }\ 2-3x = -7$ expand the plus/minus
$-3x = 5\ \text{ or }\ -3x = -9$ subtract $\,2\,$ from both sides of both equations
$\displaystyle x = -\frac{5}{3}\ \text{ or } x = 3$ divide both sides of both equations by $\,-3\,$

It’s a good idea to check your solutions:

$|2 - 3(-\frac{5}{3})|\ \overset{\text{?}}{=}\ 7$
$|2 + 5| = 7$
Check!

$|2 - 3(3)|\ \overset{\text{?}}{=}\ 7$
$|2 - 9| = 7$
Check!

Example

Solve: $5 - 2|3 - 4x| = -7$
Solution: To use the theorem, you must have the absolute value all by itself on one side of the equation. Thus, your first job is to isolate the absolute value :
$5 - 2|3 - 4x| = -7$ original equation
$-2|3 - 4x| = -12$ subtract $\,5\,$ from both sides
$|3 - 4x| = 6$ divide both sides by $\,-2\,$
$3 - 4x = \pm 6$ check that $\,k\ge 0\,$; use the theorem
$3 - 4x = 6 \text{ or } 3 - 4x = -6$ expand the plus/minus
$-4x = 3\ \text{ or }\ -4x = -9$ subtract $\,3\,$ from both sides of both equations
$\displaystyle x = -\frac{3}{4}\ \text{ or }\ x = \frac{9}{4}$ divide both sides of both equations by $\,-4\,$

Example

Solve: $|3x + 1| = -5$
Solution: The theorem can’t be used here, since $\,k\,$ is negative. In this case, you need to stop and think. Can absolute value ever be negative?  No! No matter what number you substitute for $\,x\,,$ the left-hand side of the equation will always be a number that is greater than or equal to zero. Therefore, this sentence has no solutions. It is always false.

Concept Practice

Solve the given absolute value equation. Write the result in the most conventional way.

For more advanced students, a graph is available. For example, the equation $\,|2 - 3x| = 7\,$ is optionally accompanied by the graph of $\,y = |2 - 3x|\,$ (the left side of the equation, dashed green) and the graph of $\,y = 7\,$ (the right side of the equation, solid purple). In this example, you are finding the values of $\,x\,$ where the green graph intersects the purple graph.

Click the ‘Show/Hide Graph’ button to toggle the graph.


Solve: