Need some simpler practice with absolute value and related concepts first?
- Simplifying Basic Absolute Value Expressions
- Solving Simple Absolute Value Sentences
- Solving Sentences involving ‘Plus or Minus’
Now, let's talk about the concepts involved in solving absolute value equations:
Translating the Theorem
Recall first that normal mathematical conventions dictate that ‘$\,|x| = k\ $’ represents an entire class of sentences, including the members
$|x| = 2$
$|x| = 5.7$
$|x| = \frac{1}{3}$
The variable $\,k\ $ changes from sentence to sentence, but is constant within a given sentence.
Also recall that ‘$\,x=\pm k\ $’ is a shorthand for ‘$\,x = k\,$ or $\,x = -k\,$’.
When you see a sentence of the form $\,|x| = k\ $, here’s what you should do:
- Check that $\,k\,$ is a nonnegative number (zero, or greater than zero).
- The symbol $\,|x|\,$ represents the distance between $\,x\,$ and $\,0\,.$
- Thus, you want the numbers $\,x\,,$ whose distance from $\,0\,$ is $\,k\,.$
- You can walk from $\,0\,$ in two directions: to the right, or to the left. Walk to the right a distance $\,k\,,$ and you get to the number $\,k\,.$ Walk to the left a distance $\,k\,,$ and you get to the number $\,-k\,.$
- Thus, $\,|x| = k\ $ is equivalent to $\,x = k\ \text{ or }\ x = -k\,,$ which goes by the shorthand $\,x=\pm k\,.$
- Equivalent sentences are completely interchangeable, and you can use whichever is easiest to work with. In this case, you’re getting rid of the troublesome absolute value in exchange for a less-troublesome ‘plus or minus’ sign.
Recall that ‘$\iff$’ is a symbol for ‘is equivalent to’.
The power of the sentence-transforming tool
$$\cssId{s48}{|x| = k \iff x = \pm k}$$goes far beyond solving simple sentences like $\,|x| = 5\,$!
Since $\,x\,$ can be any real number, you should think of $\,x\,$ as merely representing the stuff inside the absolute value symbols. Thus, you could think of rewriting the tool as:
$$ \cssId{s53}{|\text{stuff}| = k \iff \text{stuff} = \pm k} $$See how this idea is used in the following examples:
Example
| $|2 - 3x| = 7$ | original equation |
| $2-3x = \pm 7$ | check that $\,k\ge 0\,$; use the theorem |
| $2-3x = 7\ \text{ or }\ 2-3x = -7$ | expand the plus/minus |
| $-3x = 5\ \text{ or }\ -3x = -9$ | subtract $\,2\,$ from both sides of both equations |
| $\displaystyle x = -\frac{5}{3}\ \text{ or } x = 3$ | divide both sides of both equations by $\,-3\,$ |
It’s a good idea to check your solutions:
$|2 - 3(-\frac{5}{3})|\ \overset{\text{?}}{=}\ 7$
$|2 + 5| = 7$
Check!
$|2 - 3(3)|\ \overset{\text{?}}{=}\ 7$
$|2 - 9| = 7$
Check!
Example
| $5 - 2|3 - 4x| = -7$ | original equation |
| $-2|3 - 4x| = -12$ | subtract $\,5\,$ from both sides |
| $|3 - 4x| = 6$ | divide both sides by $\,-2\,$ |
| $3 - 4x = \pm 6$ | check that $\,k\ge 0\,$; use the theorem |
| $3 - 4x = 6 \text{ or } 3 - 4x = -6$ | expand the plus/minus |
| $-4x = 3\ \text{ or }\ -4x = -9$ | subtract $\,3\,$ from both sides of both equations |
| $\displaystyle x = -\frac{3}{4}\ \text{ or }\ x = \frac{9}{4}$ | divide both sides of both equations by $\,-4\,$ |
Example
Concept Practice
Solve the given absolute value equation. Write the result in the most conventional way.
For more advanced students, a graph is available. For example, the equation $\,|2 - 3x| = 7\,$ is optionally accompanied by the graph of $\,y = |2 - 3x|\,$ (the left side of the equation, dashed green) and the graph of $\,y = 7\,$ (the right side of the equation, solid purple). In this example, you are finding the values of $\,x\,$ where the green graph intersects the purple graph.
Click the ‘Show/Hide Graph’ button to toggle the graph.