DIVISIBILITY

The numbers $0$, $2$, $4$, $6$, … are called even numbers.
Even numbers always end in one of these digits:   $0$, $2$, $4$, $6$, or $\,8\,$.
Even numbers can always be divided into two equal (even) piles.
Note: The numbers $1$, $3$, $5$, $7$, … are called odd numbers.

The numbers $0$, $2$, $4$, $6$, … are also said to be divisible by 2.
Divisible by 2 means that $\,2\,$ goes into the number evenly.
The phrases  even  and  divisible by 2  are interchangeable.

Divisible by 3 means that $\,3\,$ goes into the number evenly.
Divisible by 4 means that $\,4\,$ goes into the number evenly; and so on.

A divisibility test is a shortcut to decide if a number is divisible by a given number.

DIVISIBILITY BY 2
If a number ends in $0$, $2$, $4$, $6$, or $8$, then the number is divisible by $\,2\,$.
Also, if a number is divisible by $\,2\,$, then it ends in $0$, $2$, $4$, $6$, or $\,8\,$.

For example, $\,87{,}356\,$ is divisible by $\,2\,$, since it ends in the digit $\,6\,$.
However, $\,87{,}357\,$ is not divisible by $\,2\,$, since it ends in the digit $\,7\,$.

There's a neat trick for deciding if a number is divisible by $\,3\,$.
The technique is illustrated with the following example:

EXAMPLE:
Question: Is $\,57{,}394\,$ divisible by $\,3\,$?
Solution: Add up the digits in the number:   $5 + 7 + 3 + 9 + 4 = 28\;$.
The sum is $\,28\,$; add up the digits again:   $2 + 8 = 10\,$.
Since $\,10\,$ is not divisible by $\,3\,$, the original number $\,57{,}394\,$ is also not divisible by $\,3\,$.
DIVISIBILITY BY 3
To decide if a number is divisible by $\,3\,$, add up the digits in the number.
Continue this process of adding the digits until you get a manageable number.
(If you want, keep going until you get a single-digit number.)
If this final number is divisible by $\,3\,$, then the number you started with is also divisible by $\,3\,$.
If this final number is not divisible by $\,3\,$, then the number you started with is not divisible by $\,3\,$.

☆ (speed-it-up trick!)
Let's re-do the previous example, being a bit more clever.
You don't really have to add up all the digits!
Looking at the number $\,57{,}394\,$, the digits $\,3\,$ and $\,9\,$ are clearly divisible by $\,3\,$.
So, don't bother including them in your sum!
That leaves you with $\,5\,$, $\,7\,$ and $\,4\,$.
But, the sum of $\,5\,$ and $\,7\,$ is $\,12\,$, which is divisible by $\,3\,$.
So, you're really only left with the digit $\,4\,$, which is clearly not divisible by $\,3\,$.
If you get into the habit of discarding $\,3\,$'s, $\,9\,$'s, and obvious sums that give a multiple of $\,3\,$ (like $\,5 + 7\,$), then this test can go much faster!

DIVISIBILITY BY 5
If a number ends in $\,0\,$ or $\,5\,$, then the number is divisible by $\,5\,$.
Also, if a number is divisible by $\,5\,$, then it ends in $\,0\,$ or $\,5\,$.
DIVISIBILITY BY 10
If a number ends in $\,0\,$, then the number is divisible by $\,10\,$.
Also, if a number is divisible by $\,10\,$, then it ends in $\,0\,$.

More compactly, we can say that a number is divisible by 10 if and only if it ends with a 0.

Master the ideas from this section
by practicing both exercises at the bottom of this page.

When you're done practicing, move on to:
Basic Properties of Zero and One

Decide if the number is divisible by:   2, 3, 5, 10.
Check all appropriate boxes.

2 3 5 10

CONCEPT QUESTIONS EXERCISE:
On this exercise, you will not key in your answer.
However, you can check to see if your answer is correct.
 (MAX is 12; there are 12 different problem types.)